Chemistry - Hydrogen and Its compound Question with Solution | TestHub

$30\%$ solution of ${\mathrm{H}}_2{\mathrm{O}}_2$ is known as perhydrol ${\mathrm{H}}_2{\mathrm{O}}_2$ decomposes as $$2{\mathrm{H}}_2{\mathrm{O}}_2⟶2{\mathrm{H}}_2\mathrm{O}+{\mathrm{O}}_2$$ Volume strength of $30\%{\mathrm{H}}_2{\mathrm{O}}_2$ solution is 100 i.e., $1\mathrm{mL}$ of this solution on decomposition gives $100\mathrm{mL}$ oxygen. ${\mathrm{SO}}_2+\frac{1}{2}{\mathrm{O}}_2⟶{\mathrm{SO}}_3$ $1\mathrm{L}\frac{1}{2}\mathrm{L}$ 2L $1\mathrm{L}2\mathrm{L}$ Since, $100\mathrm{mL}$ of oxygen is obtained by $$=1\mathrm{mL}\text{ of }{\mathrm{H}}_2{\mathrm{O}}_2$$ $\therefore 1000\mathrm{mL}$ of oxygen will be obtained by $$=\frac{1}{100}\times 1000\mathrm{mL}\text{ of }{\mathrm{H}}_2{\mathrm{O}}_2=10\mathrm{mLof}{\mathrm{H}}_2{\mathrm{O}}_2$$