Chemistry - Hydrocarbon Question with Solution | TestHub
ChemistryHydrocarbonMETHOD OF PREPARATION OF ALKENESMedium2 min
ChemistryMediumsingle choice
The dehydrohalogenation of CH₃–CHBr–CH₂Br with one equivalent of alcoholic KOH gives:
Options:
Answer:
Solution:
Concepts: Dehydrohalogenation, E2 elimination, Zaitsev's rule. One equivalent of alcoholic KOH favors elimination of HBr, forming the more substituted alkene.Solution: A
Stream:JEESubject:ChemistryTopic:HydrocarbonSubtopic:METHOD OF PREPARATION OF ALKENES
⏱ 2m
Doubts & Discussion
Loading discussions...