Deuterioethane on chlorination reacts as follows:
$C_{2} H_{5} - D + C l_{2} ⟶ A (7%) C_{2} H_{5} - Cl + D - Cl + B (93%) C_{2} H_{4} D - Cl + H - Cl$ ,
What is the reactivity ratio of H : D.

Question

Deuterioethane on chlorination reacts as follows:

$C_{2} H_{5} - D + C l_{2} ⟶ A (7%) C_{2} H_{5} - Cl + D - Cl + B (93%) C_{2} H_{4} D - Cl + H - Cl$ ,

What is the reactivity ratio of H : D.

TestHub · Accepted Answer

C 2 ​ H 5 ​ − D + C l 2 ​ ⟶ A ( 7% ) C 2 ​ H 5 ​ − Cl + D − Cl ​ ​ + B ( 93% ) C 2 ​ H 4 ​ D − Cl + H − Cl ​ ​ ​ W e i g h t o f ( B ) W e i g h t o f ( A ) ​ = ( R e a c t i v i t yo f H R e a c t i v i t yo f D ​ ) × ( P ro babi l i t yo f H P ro babi l i t yo f D ​ ) 93 7 ​ = ( R e a c t i v i t yo f H R e a c t i v i t yo f D ​ ) × 5 1 ​ ( R e a c t i v i t yo f D R e a c t i v i t yo f H ​ ) = 35 93 ​ ​

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