Chemistry - Hydrocarbon Question with Solution | TestHub

ChemistryHydrocarbonREDUCTIONMedium2 minQB

ChemistryMediummatching list

The given compound $X$ is treated with the reagents in List -I to give the product(s) in List-II.

Answer:

Solution:

$LiAlH_{4}$ reduces epoxide, $COOH, NO_{2}, COCl$ and $CO \overline{O} Et$ groups.

$H_{2} / Pd - BaSO_{4} -$ Quinoline reduces acyl halide to aldehyde and alkyne to cis-alkene.

$B_{2} H_{6} / THF$ selectively reduces acid to alcohol.

$H_{2} / Pd - C$ reduces $NO_{2}$ , triple bond, double bond and COCl .

Stream:JEESubject:ChemistryTopic:HydrocarbonSubtopic:REDUCTION

⏱ 2mℹ️ Source: QB

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