Chemistry - Hydrocarbon Question with Solution | TestHub

ChemistryHydrocarbonMiscellaneous/MixedMedium2 minQB
ChemistryMediumsingle choice
Passage / Comprehension

Answer the following questions based on given reaction

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Total number of theoretically products (including stereo)

Options:

Answer:
C
Solution:

Question Explanation:

The question asks how many distinct products are theoretically possible when the given substituted

cyclopropane undergoes free-radical monochlorination, counting all constitutional and stereoisomers.

Concept: This question is based on free radical halogenation reaction.

Solution:

Substitution on CH3 (a): Product is 1-chloro-1-ethylcyclopropane. No chiral center. → 1 product

Substitution on CH2 (b): Product is 1-(1-chloroethyl)cyclopropane. One chiral center. → 2

products (R and S enantiomers).

Substitution on C1H (c): Product is 1-chloro-1-ethylcyclopropane. No chiral center. → 1 product.

(Wait, this is the same structural isomer as (1). Let's re-read the question. The substitution must be

on a C–H bond. So a, b, c, d are the non-equivalent H atoms. The product from a and c is the same

structural isomer: 1–chloro–1-ethylcyclopropane. → Count as 1 product.)

Substitution on C2H2 or C3H2 (d/e): Product is 2-chloro-1-ethylcyclopropane. Two chiral centers

(C1 and C2 ). This leads to two pairs of enantiomers: cis (R, R and S, S) and trans (R, S and S, R).

→ 4 products.

Free-radical monochlorination occurs at all available C-H bonds. The product is formed by substituting one H atom with one Cl atom.

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Total number of products (including stereo): 1 + 2 + 1 + 4 = 8

 

Stream:JEESubject:ChemistryTopic:HydrocarbonSubtopic:Miscellaneous/Mixed
2mℹ️ Source: QB

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