Chemistry - Hydrocarbon Question with Solution | TestHub

ChemistryHydrocarbonMiscellaneous/MixedMedium2 minQB
ChemistryMediumsingle choice
Passage / Comprehension

At a certain temperature, the percentage of monochlorinated products obtained for the following reaction are given:

image.png

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For all questions, assume the reactivity ratio to be the same as in the above reactions.

The propagation step of monochlorination of an alkane involves the formation of a radical intermediate.

R–H + Cl R + H–Cl

The energy profile for the formation of a free radical is described as:

image.png

 

For the compound (X):

image.png

Which of the following is incorrect for the monochlorination of ?

Consider the reactivity order of chlorination as follows:

3°H : 2°H : 1°H

4.5 : 3.8 : 1

Options:

Answer:
B
Solution:

Question Explanation:

The question asks to identify the incorrect statement related to the monochlorination of 1,3,5-

trimethylcyclohexane.

Concept:

This question is based on free-radical halogenation and analysis of the possible monochlorinated

products.

Solution: From the given energy diagram

image.png

Reactivity order (approx.): Cl2 /hν

3° : 2° : 1° ≈ 4.5 : 3.8 : 1

For Chlorination 9 × 1 = 9 1° product =

6 × 3.8 = 22.8 2° product =

3 × 4.5 = 13.5 3° product =

Total = 45.3

Via intermediate (R), two products are obtained which are enantiomers is incorrect they are geometrical diastereomers

 

 

 

Stream:JEESubject:ChemistryTopic:HydrocarbonSubtopic:Miscellaneous/Mixed
2mℹ️ Source: QB

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