Chemistry - Hydrocarbon Question with Solution | TestHub
Product can be-
Options:(select one or more)
Answer:
Solution:
Alkene CH₂=CH–CH₃ (propene) reacts with NBS/CCl₄, Δ → allylic bromination occurs (not addition).
Bromine substitutes at allylic position forming allyl bromide (CH₂=CH–CH₂Br) with resonance-stabilized radical.
This allyl bromide shows resonance → structure can shift double bond position.
Now treatment with Na/dry ether (Wurtz reaction) causes coupling of two allyl radicals.
Due to resonance, different coupling modes are possible → giving multiple products.
Products formed include conjugated and cumulated dienes depending on bonding positions.
Hence, structures corresponding to A, C, and D are possible.
Option B is not formed because it doesn’t match resonance-assisted coupling pattern.