In the following sequence of reactions, C 3 H 6 ⟶ H + / H 2 O A KIO dilKOH B + C . The compounds B and C respectively are :

CH 3 CH = CH 2 ⟶ H + / H 2 O CH 3 CHOHCH 3 KIO dil KOH CHI 3 + CH 3 COOK

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Chemistry - Hydrocarbon Question with Solution | TestHub

ChemistryHydrocarbonCHEMICAL REACTIONS OF ALKENESMedium2 minPYQ_2021

ChemistryMediumsingle choice

In the following sequence of reactions, $C_{3} H_{6} \overset{H^{+} / H_{2} O}{⟶} A \frac{KIO}{dilKOH} B + C$ . The compounds $B$ and $C$ respectively are :

Options:

Answer:

Solution:

${CH}_{3} CH = {CH}_{2} \overset{H^{+} / H_{2} O}{⟶} {CH}_{3} {CHOHCH}_{3} \frac{KIO}{dil KOH} {CHI}_{3} + {CH}_{3} COOK$

Stream:JEESubject:ChemistryTopic:HydrocarbonSubtopic:CHEMICAL REACTIONS OF ALKENES

⏱ 2mℹ️ Source: PYQ_2021

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