Chemistry - Hydrocarbon Question with Solution | TestHub

As$\mathrm{C}{\mathrm{H}}_2=\mathrm{C}\mathrm{H}-\mathrm{B}\mathrm{r}$has partial C – Br double bond character, so it requires stronger base to remove HBr that is why KOH is ignored and$\mathrm{N}\mathrm{a}\mathrm{N}{\mathrm{H}}_2$is used.