Chemistry - Hydrocarbon Question with Solution | TestHub

${\mathrm{CH}}_3-\mathrm{CO}-{\mathrm{CH}}_3\frac{{\mathrm{CH}}_3\mathrm{Mg}\mathrm{I}/\text{ ether }}{{\mathrm{H}}_3{\mathrm{O}}^{+}}$

${\mathrm{CH}}_3-\mathrm{CH}={\mathrm{CH}}_2\frac{(\text{ i) }{\mathrm{B}}_2{\mathrm{H}}_6}{\text{ (ii) }{\mathrm{H}}_2{\mathrm{O}}_2}$

${\mathrm{CH}}_3-\mathrm{CH}={\mathrm{CH}}_2\frac{\text{ (i) cold.conc }{\mathrm{H}}_2{\mathrm{SO}}_4}{\text{ (ii) }{\mathrm{H}}_2\mathrm{O}}$

$\mathrm{H}-\mathrm{CH}0\frac{{\mathrm{c}}_2{\mathrm{H}}_5\mathrm{Mg}\mathrm{Br}/\mathrm{ether}}{{\mathrm{H}}_3{\mathrm{O}}^{+}}$