In the reaction C H 3 - C ≡ C - H → ( i ) N a N H 2 / N H 3 ( l ) ( A ) → C H 3 - C H 2 - C H 2 - B r ( B ) The product B is

Here propyne is converted into hex-2-yne. CH 3 − C ≡ C − H → NaNH 2 / NH 3 l CH 3 − C ≡ C − Na ⊕ → CH 3 − CH 2 − CH 2 − Br CH 3 − C ≡ C − CH 2 − CH 2 − CH 3

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Chemistry - Hydrocarbon Question with Solution | TestHub

ChemistryHydrocarbonCHEMICAL REACTIONS OF ALKYNESEasy2 minPYQ_2020

ChemistryEasysingle choice

In the reaction
$C H_{3} - C \equiv C - H \overset{(i) N a N H_{2} / N H_{3} (l)}{\to} (A) \overset{C H_{3} - C H_{2} - C H_{2} - B r}{\to} (B)$
The product B is

Options:

Answer:

Solution:

Here propyne is converted into hex-2-yne.
${CH}_{3} - C \equiv C - H \overset{{NaNH}_{2} / {NH}_{3} (l)}{\to} {CH}_{3} - C \equiv \bar{C} \overset{\oplus}{Na} \overset{{CH}_{3} - {CH}_{2} - {CH}_{2} - Br}{\to} {CH}_{3} - C \equiv C - {CH}_{2} - {CH}_{2} - {CH}_{3}$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:HydrocarbonSubtopic:CHEMICAL REACTIONS OF ALKYNES

⏱ 2mℹ️ Source: PYQ_2020

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