Chemistry - Hydrocarbon Question with Solution | TestHub

$\mathrm{C}{\mathrm{H}}_4\stackrel{\mathrm{C}{\mathrm{l}}_2}{\to }\mathrm{C}{\mathrm{H}}_3\mathrm{C}\mathrm{l}\stackrel{\mathrm{C}{\mathrm{l}}_2}{\to }\mathrm{C}{\mathrm{H}}_2\mathrm{C}{\mathrm{l}}_2\stackrel{\mathrm{C}{\mathrm{l}}_2}{\to }\mathrm{C}\mathrm{H}\mathrm{C}{\mathrm{l}}_3\stackrel{\mathrm{C}{\mathrm{l}}_2}{\to }\mathrm{C}\mathrm{C}{\mathrm{l}}_4$
Since this reaction takes place by free radical mechanism. Hence, there is a possibility of formation of ethane.
$\underset{\text{Methyl}\text{free}\text{radicals}}{\stackrel{•}{\text{C}}{\text{H}}_{\text{3}}\text{+}\stackrel{•}{\text{C}}{\text{H}}_{\text{3}}}\to \underset{\text{Ethane}}{{\text{CH}}_{\text{3}}-{\text{CH}}_{\text{3}}}$