Chemistry - Hydrocarbon Question with Solution | TestHub

Key idea $\mathrm{pi}$-bond do not participate in hybridisation

In H−C≡C−C=−H all carbon atoms are in same hybridization state i.e., sp​ hybridized.

a. $\mathrm{H}-\stackrel{\mathrm{sp}}{\mathrm{C}}\equiv \stackrel{\mathrm{sp}}{\mathrm{C}}-\stackrel{\mathrm{sp}}{\mathrm{C}}\equiv \stackrel{\mathrm{sp}}{\mathrm{C}}-\mathrm{H}$

b. $\stackrel{{\mathrm{sp}}^3}{{\mathrm{CH}}_3}-\stackrel{\mathrm{sp}}{\mathrm{C}}\equiv \stackrel{\mathrm{sp}}{\mathrm{C}}-\stackrel{{\mathrm{sp}}^3}{{\mathrm{CH}}_3}$

c. $\underset{{\mathrm{sp}}^2}{{\mathrm{CH}}_2}=\underset{\mathrm{sp}}{\mathrm{C}}=\stackrel{{\mathrm{sp}}^2}{{\mathrm{CH}}_2}$

d. $\underset{{\mathrm{sp}}^2}{{\mathrm{CH}}_2}=\underset{{\mathrm{sp}}^2}{\mathrm{CH}-}\underset{\mathrm{sp}}{\mathrm{C}}\equiv \underset{\mathrm{sp}}{\mathrm{CH}}$