Chemistry - Hydrocarbon Question with Solution | TestHub

$\begin{array}{l}\text{Br}\\ {\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{CH}={\mathrm{CH}}_2\underset{{\mathrm{H}}_2{\mathrm{O}}_2}{\overset{\mathrm{HBr}}{\to }}{\mathrm{CH}}_3{\mathrm{CH}}_2\underset{|}{\mathrm{CH}}-\stackrel{|}{{\mathrm{CH}}_2}\stackrel{{\mathrm{C}}_2{\mathrm{H}}_5\mathrm{ONa}}{\to }{\mathrm{CH}}_3-{\left({\mathrm{CH}}_2\right)}_3-{\mathrm{OCH}}_2-{\mathrm{OCH}}_2{\mathrm{CH}}_3\\ \text{H}\end{array}$
$\mathrm{H}\mathrm{B}\mathrm{r}$in presence of peroxide gives anti Markovnikoff addition product.
$1^{\mathrm{o}}$alkyl halide on reaction with${\mathrm{C}}_2{\mathrm{H}}_5\mathrm{O}\mathrm{N}\mathrm{a}$gives${\mathrm{S}}_{\mathrm{N}}2$reaction.