Chemistry - Hydrocarbon Question with Solution | TestHub

Electrolysis of a concentrated aqueous solution of either sodium or potassium salts of saturated carboxylic acids yields higher alkane at anode. $$2\mathrm{RCOOK}\underset{\text{ Oxidation }}{\mathrm{Electrolytic}}⟶\underset{\text{ Anode }}{2{\mathrm{RCOO}}^{-}}+\underset{\text{ Cathod }}{2{\mathrm{K}}^{+}}$$ At anode $2{\mathrm{RCOO}}^{-}\to 2\mathrm{RCOO}+2{\mathrm{e}}^{-}⟶$ $$\mathrm{R}-\mathrm{R}+2{\mathrm{CO}}_2$$ At Cathode $2{\mathrm{K}}^{+}+2{\mathrm{e}}^{-}\to 2\mathrm{K}$ $$2\mathrm{K}+{\mathrm{H}}_2\mathrm{O}\to 2\mathrm{KOH}+{\mathrm{H}}_2\uparrow$$ (Kolbe's Method)