Assertion : HC ≡ C − is more stable than H 2 C = CH − . Reason : HC ≡ C − has more s-character than H 2 C = CH −

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Chemistry - Hydrocarbon Question with Solution | TestHub

ChemistryHydrocarbonCHEMICAL REACTIONS OF ALKYNESHard2 minPYQ_2012

ChemistryHardsingle choice

Assertion : $HC \equiv C^{-}$ is more stable than $H_{2} C = CH^{-}$ .Reason : $HC \equiv C^{-}$ has more s-character than $H_{2} C = CH^{-}$

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Answer:

Solution:

$HC \equiv C^{-}$ has $50%$ s-character and $H_{2} C = CH^{-}$ has $33%$ s-character. Stability of carbanions increases with an increase in the s-character at the carbanion. So $HC \equiv C^{-}$ is more stable than $H_{2} C = CH^{-}$ .

Stream:AIIMSSubject:ChemistryTopic:HydrocarbonSubtopic:CHEMICAL REACTIONS OF ALKYNES

⏱ 2mℹ️ Source: PYQ_2012

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