Chemistry - Hydrocarbon Question with Solution | TestHub

Reaction of $\mathrm{HBr}$ with propene in the presence of peroxide gives $n$-propyl bromide. This addition reaction is an example of anti-Markownikoffs addition reaction.
Related Theory Step 1: Peroxide undergoes fission to give free radicals. $$\mathrm{R}-\mathrm{O}-\mathrm{O}-\mathrm{R}⟶2\mathrm{R}-\dot{\mathrm{O}}$$ Step 2: $\mathrm{HBr}$ combines with free radical to form bromine free radical. $$R-\dot{O}+\mathrm{HBr}⟶\mathrm{R}-\mathrm{OH}+\dot{\mathrm{B}}$$ Step 3: $\dot{B}$ attacks the double bond of the alkene to form a more stable free radical.
Step 4: More stable free radical attacks the $\mathrm{HBr}$. $$\begin{array}{rl}{\mathrm{CH}}_3\dot{\mathrm{C}}{\mathrm{CHH}}_2\mathrm{Br}+\mathrm{HBr}⟶& {\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{Br}+\dot{\mathrm{B}}\\ & \text{ n-propylbromide }\end{array}$$ Step 5: $\dot{B}r+\dot{B}r⟶B{r}_2$