3-Bromo-4-methylheptane reacts with C H 3 C H 2 O − / C H 3 C H 2 OH . What is the total number of products obtained in the reaction considering CH₃CH₂O⁻ only as strong base.

Question

3-Bromo-4-methylheptane reacts with C H 3 ​ C H 2 ​ O − / C H 3 ​ C H 2 ​ OH . What is the total number of products obtained in the reaction considering CH₃CH₂O⁻ only as strong base.

TestHub · Accepted Answer

E2 gives 4-methylhept-2-ene and 4-methylhept-3-ene. The first has E/Z plus a surviving C4 stereocentre (four stereoisomers); the second has E/Z only (two). Total six across unspecified starting stereoisomers. A single specified starting configuration would require a separate stereospecific count.

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Chemistry - Halogen Derivative Question with Solution | TestHub

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