When (R)-2-bromobutane is heated with water, the $S_{N} 1$ reaction proceeds twice as fast as $S_{N} 2$ pathway. Calculate the specific rotation expected for the product(s) in degrees.
(The specific rotation of (R)-butan-2-ol is –13.5º)

Question

When (R)-2-bromobutane is heated with water, the $S_{N} 1$ reaction proceeds twice as fast as $S_{N} 2$ pathway. Calculate the specific rotation expected for the product(s) in degrees.

(The specific rotation of (R)-butan-2-ol is –13.5º)

TestHub · Accepted Answer

% S N ​ 1 = 66.67% % S N ​ 2 = 33.33% The product mixture contains 66.67% (S)-butan-2-ol and 33.33% (R)-butan-2-ol

Chemistry - Halogen Derivative Question with Solution | TestHub

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