Chemistry - Halogen Derivative Question with Solution | TestHub

ChemistryHalogen DerivativeFREE RADICAL SUBSTITUTION and ReactionMedium2 minQB

ChemistryMediumsingle choice

$PhCH_{3} NBS (A) CN^{-} (B)$

The product (B) in the sequence is:

Answer:

Solution:

$P h C H_{3} + NBS h ν P h C H_{2} B r (A)$

$P h C H_{2} B r + C N^{-} ⟶ P h C H_{2} CN (B) + B r^{-}$

Stream:JEESubject:ChemistryTopic:Halogen DerivativeSubtopic:FREE RADICAL SUBSTITUTION and Reaction

⏱ 2mℹ️ Source: QB

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