Identify the major product obtained when 2-Bromobutane is heated with alcoholic KOH.

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TestHub · Accepted Answer

When 2-Bromobutane is heated with alcoholic KOH, it undergoes dehydrohalogenation (E2 elimination).

The reaction can yield two possible alkene products depending on which $β$ -hydrogen is eliminated:

$C H_{3} - C H (B r) - C H_{2} - C H_{3} a l c . K O H, Δ C H_{3} - C H = C H - C H_{3} + C H_{2} = C H - C H_{2} - C H_{3}$

According to Zaitsev's rule, the more highly substituted alkene is formed as the major product because it is more stable.

But-2-ene is a disubstituted alkene, whereas But-1-ene is a monosubstituted alkene.

Therefore, But-2-ene is the major product.

Answer: But-2-ene

Chemistry - Halogen Derivative Question with Solution | TestHub

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