Chemistry - Halogen Derivative Question with Solution | TestHub

The chemical reaction is:

${\mathrm{C}}_2{\mathrm{H}}_5\mathrm{Cl}+\mathrm{KOH}\to {\mathrm{C}}_2{\mathrm{H}}_5\mathrm{OH}+\mathrm{KCl}$

The formula for percentage atom economy is:

$\text{Percentage atom economy}=\frac{\text{Mass of desired product}}{\text{Sum of masses of all reactants}}\times 100$

Mass of the desired product (ethanol) = $46\mathrm{g}$

Sum of masses of all reactants = $64.5\mathrm{g}+56\mathrm{g}=120.5\mathrm{g}$

$\text{Percentage atom economy}=\frac{46}{120.5}\times 100=38.17\%$

Answer: $38.17\%$