Chemistry - Halogen Derivative Question with Solution | TestHub

The reaction of an alkyl halide with a silver salt of a carboxylic acid yields an ester.

In this reaction, ethyl bromide (${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{Br}$) reacts with silver acetate (${\mathrm{CH}}_3\mathrm{COOAg}$). The acetate ion (${\mathrm{CH}}_3{\mathrm{COO}}^{-}$) acts as a nucleophile and attacks the electrophilic carbon of the ethyl group, displacing the bromide ion.

${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{Br}+{\mathrm{CH}}_3\mathrm{COOAg}\stackrel{\Delta }{\to }{\mathrm{CH}}_3{\mathrm{COOCH}}_2{\mathrm{CH}}_3+\mathrm{AgBr}$

The product $x$ formed is ethyl acetate (${\mathrm{CH}}_3{\mathrm{COOCH}}_2{\mathrm{CH}}_3$).

Answer: ${\mathrm{CH}}_3{\mathrm{COOCH}}_2{\mathrm{CH}}_3$