Chemistry - Halogen Derivative Question with Solution | TestHub

Methyl iodide reacts with potassium cyanide to undergo nucleophilic substitution, forming methyl cyanide as product A.

${\mathrm{CH}}_3\mathrm{I}+\mathrm{KCN}\to {\mathrm{CH}}_3\mathrm{CN}+\mathrm{KI}$

Methyl cyanide (A) undergoes Mendius reduction in the presence of sodium and ethanol to form ethylamine as product B.

${\mathrm{CH}}_3\mathrm{CN}+4[\mathrm{H}]\stackrel{\mathrm{Na}/{\mathrm{C}}_2{\mathrm{H}}_5\mathrm{OH}}{\to }{\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{NH}}_2$

Answer: ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{NH}}_2$