Chemistry - Halogen Derivative Question with Solution | TestHub

Rate of${\mathrm{S}}_{\mathrm{N}}2$reaction is as follows:
Rate = [alkyl halide]$��$[nucleophile]
Rate (initially)$=\left[{\mathrm{C}}_1\right]\left[{\mathrm{C}}_2\right]$
At new concentration
$\mathrm{R}\mathrm{a}\mathrm{t}\mathrm{e}\left(\mathrm{f}\mathrm{i}\mathrm{n}\mathrm{a}\mathrm{l}\mathrm{l}\mathrm{y}\right)=\left[3{\mathrm{C}}_1\right]\left(\frac{{\mathrm{C}}_2}{2}\right)=1.5\times \left(\left[{\mathrm{C}}_1\right]\left[{\mathrm{C}}_2\right]\right)$
$\text{Rate }\left(\text{final}\right)\text{=}\text{1}\text{.5}\text{×}\text{Rate }\left(\text{initial}\right)$