Chemistry - Halogen Derivative Question with Solution | TestHub

Here the final product Z is benzoic acid which is formed as follows
${\mathrm{C}}_6{\mathrm{H}}_5\mathrm{N}{\mathrm{H}}_2\stackrel{\mathrm{N}\mathrm{a}\mathrm{N}{\mathrm{O}}_2+\mathrm{H}\mathrm{C}\mathrm{l}}{\to }\underset{\left(\mathrm{X}\right)}{{\mathrm{C}}_6{\mathrm{H}}_5{\stackrel{+}{\mathrm{N}}}_2\mathrm{C}{\mathrm{l}}^{-}}\stackrel{\mathrm{C}\mathrm{u}\mathrm{C}\mathrm{N}}{\to }\underset{\left(\mathrm{Y}\right)}{{\mathrm{C}}_6{\mathrm{H}}_5\mathrm{C}\mathrm{N}}\stackrel{{\mathrm{H}}^{+}/{\mathrm{H}}_2\mathrm{O}}{\to }\underset{\mathrm{b}\mathrm{e}\mathrm{n}\mathrm{z}\mathrm{o}\mathrm{i}\mathrm{c}\mathrm{a}\mathrm{c}\mathrm{i}\mathrm{d}\left(\mathrm{Z}\right)}{{\mathrm{C}}_6{\mathrm{H}}_5\mathrm{C}\mathrm{O}\mathrm{O}\mathrm{H}}$