Chemistry - Halogen Derivative Question with Solution | TestHub

Acid-hydrolysis of benzonitrile forms benzoic acid.
${\mathrm{C}}_6{\mathrm{H}}_5\mathrm{C}\mathrm{N}\stackrel{{\mathrm{H}}_3{\mathrm{O}}^{+}}{\to }{\mathrm{C}}_6{\mathrm{H}}_5\mathrm{C}\mathrm{O}\mathrm{N}{\mathrm{H}}_2\stackrel{{\mathrm{H}}_3{\mathrm{O}}^{+}}{\to }{\mathrm{C}}_6{\mathrm{H}}_5\mathrm{C}\mathrm{O}\mathrm{O}\mathrm{H}+\mathrm{N}{\mathrm{H}}_4^{+}$
Note: Alkaline-hydrolysis of cyanide forms benzoate and$\mathrm{N}{\mathrm{H}}_3$.
${\mathrm{C}}_6{\mathrm{H}}_5\mathrm{C}\mathrm{N}\stackrel{{\mathrm{H}}_2\mathrm{O}/\mathrm{O}{\mathrm{H}}^{-}}{\to }{\mathrm{C}}_6{\mathrm{H}}_5\mathrm{C}\mathrm{O}\mathrm{N}{\mathrm{H}}_2\stackrel{{\mathrm{H}}_2\mathrm{O}/\mathrm{O}{\mathrm{H}}^{-}}{\to }{\mathrm{C}}_6{\mathrm{H}}_5\mathrm{C}\mathrm{O}{\mathrm{O}}^{-}+\mathrm{N}{\mathrm{H}}_3$