Chemistry - Halogen Derivative Question with Solution | TestHub

Halogenated compounds on treatment with aq. $\mathrm{KOH}$ form alcohols. The halogen atom is substituted by - $\mathrm{OH}$ group. $$\begin{array}{rl}& {\mathrm{CH}}_3\mathrm{CH}(\mathrm{Cl}){\mathrm{CH}}_2-{\mathrm{CH}}_2\mathrm{OH}\underset{\text{ aq. }\mathrm{KOH}}{⟶}\\ & {\mathrm{CH}}_3\mathrm{CH}(\mathrm{OH}){\mathrm{CH}}_2-{\mathrm{CH}}_2\mathrm{OH}\end{array}$$ Here ${\mathrm{OH}}^{-}$acts as a nucleophile.