Choose the answer that has the molecular orbitals of the allyl cation ( $C H_{2} = CH - C H_{2}^{+}$ ) correctly identified. The three pi molecular orbitals are drawn below (shaded and unshaded lobes show opposite phase).
(I) (II) (III)

Question

Choose the answer that has the molecular orbitals of the allyl cation ( $C H_{2} = CH - C H_{2}^{+}$ ) correctly identified. The three pi molecular orbitals are drawn below (shaded and unshaded lobes show opposite phase).

(I) structure (II) (III)

TestHub · Accepted Answer

The allyl cation has 2 pi electrons. They fill the lowest orbital (I, all lobes in phase), which is therefore bonding and the HOMO.

The orbital with one node through the central carbon (II) is non-bonding and empty, so it is the LUMO. The orbital with two nodes (III) is antibonding.

Chemistry - GOC Question with Solution | TestHub

Options:

Doubts & Discussion