Arrange the following compounds in decreasing order of heat of combustion.
(I)
(II)
(III)

Question

Arrange the following compounds in decreasing order of heat of combustion. (I) (II) (III)

TestHub · Accepted Answer

Heat of combustion rises with the number of carbon atoms, so (III), with 7 carbons, is the largest. (I) and (II) both have 6 carbons. For isomers the heat of combustion is proportional to 1/stability. The cyclobutane ring of (I) is more strained than the cyclopentane ring of (II), so I $>$ II.

Order : III $>$ I $>$ II.

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