Chemistry - GOC Question with Solution | TestHub

$\mathrm{NaN}{\mathrm{H}}_2$ removes the two most acidic protons. The acidic sites are O-H ($\mathrm{p}{K}_{\mathrm{a}}$ ≈ 16), the terminal alkyne C-H ($\mathrm{p}{K}_{\mathrm{a}}$ ≈ 25), and the vinylic C-H ($\mathrm{p}{K}_{\mathrm{a}}$ ≈ 44). The two lowest $\mathrm{p}{K}_{\mathrm{a}}$ values belong to the O-H and the terminal alkyne C-H, so the product carries the alkoxide ${\mathrm{O}}^{-}$ and the acetylide $\mathrm{C}\equiv {\mathrm{C}}^{-}$ : option (C).