Chemistry - GOC Question with Solution | TestHub
ChemistryGOCAcid BaseEasy2 minQB
ChemistryEasysingle choice
For the following compound, treatment with 2 moles of NaNH₂ gives product (A).
The product (A) will be.
Options:
Answer:
C
Solution:
NaNH₂ removes the two most acidic protons. The acidic sites are O-H (pKa ≈ 16), the terminal alkyne C-H (pKa ≈ 25), N-H (pKa ≈ 38) and the vinylic C-H (pKa ≈ 44). The two lowest pKa values belong to the O-H and the terminal alkyne C-H, so the product carries the alkoxide O⁻ and the acetylide C≡C⁻ : option (C).
Stream:JEESubject:ChemistryTopic:GOCSubtopic:Acid Base
⏱ 2mℹ️ Source: QB
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