Chemistry - GOC Question with Solution | TestHub
ChemistryGOCBond Length, Strength, Cleavage, Rotational Energy BarrierMedium2 minQB
ChemistryMediumsingle choice
The dianion of squaric acid (squarate ion, C₄O₄²-) is a resonance hybrid. How many equivalent resonance structures, each with two C=O groups, one ring C=C and two O⁻, can be written for it ?

Options:
Answer:
A
Solution:
Each resonance structure has two O⁻ groups on neighbouring carbons, one ring C=C between them, and two C=O groups. The two O⁻ can sit on any of the four edges of the square, giving 4 structures. A structure with O⁻ on diagonal carbons is impossible because the other two carbons would have no partner for a C=C bond.
Number of structures = 4. The charge is spread over all four oxygens, which is why the ion is more stable than acetate.
Stream:JEESubject:ChemistryTopic:GOCSubtopic:Bond Length, Strength, Cleavage, Rotational Energy Barrier
⏱ 2mℹ️ Source: QB
Doubts & Discussion
Loading discussions...
