Chemistry - GOC Question with Solution | TestHub

${\mathrm{H}}_1$ is on an allylic carbon, ${\mathrm{H}}_2$ on a secondary alkyl carbon and ${\mathrm{H}}_3$ on a primary carbon. Radical stability : allylic $>$ secondary $>$ primary, so the bond strength is the reverse : 3 $>$ 2 $>$ 1.