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ChemistryGOCAromaticityHard2 minQB
ChemistryHardnumerical

X = number of reactions in which an aromatic compound is formed. Find the value of (X - 4). (No reagent is shown for (e).)

(a) structure A

(b) structure A

(c) structure A

(d) structure A

(e) structure

(f) structure A

(g) structure 2Na

(h) structure 3PhLi

(i) structure HBr

(j) structure HBr

(k) structure HI

(l) structure , Δ

(m) structure HBr

(n) structure 2Na

Answer:
3.00
Solution:

(a) The product is the cyclopropyl cation, which has no π electrons in the ring : not aromatic. (b) The product is the cyclopropenyl cation (2π) : aromatic. (c) Cl is on an carbon, so a vinyl cation forms : not aromatic. (d) The product is the cyclopentadienyl cation (4π) : anti-aromatic. (e) No reagent, no reaction. (f) The product is the tropylium ion (6π) : aromatic. (g) 2Na converts tub-shaped cyclooctatetraene into its dianion (10π) : aromatic. (h) PhLi cannot give an aromatic species from this diene : no. (i) HBr protonates OH, water leaves and the cyclopropenyl cation (2π) forms : aromatic. (j) HBr adds to the C=C to give bromocyclopropane : no. (k) HI protonates the triene and gives a non-aromatic cycloheptadienyl cation : no. (l) Dewar benzene rearranges to benzene with and heat : aromatic. (m) HBr protonates the C=O oxygen and gives the hydroxytropylium ion (6π) : aromatic. (n) 2Na gives the cyclobutadiene dianion (6π) : aromatic. Aromatic products form in (b), (f), (g), (i), (l), (m) and (n) : X = 7, so X - 4 = 3.

Stream:JEESubject:ChemistryTopic:GOCSubtopic:Aromaticity
⏱ 2mℹ️ Source: QB

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