Propanoic acid is treated separately with two reagents.
EtCOOH + $NaN H_{2}$ $\to$ $EtCO O^{-} N a^{+}$ + gas A
EtCOOH + NaH $\to$ $EtCO O^{-} N a^{+}$ + gas B
If A and B are the molar masses of the two gases, find the value of A + B - 14.

Question

Propanoic acid is treated separately with two reagents.

structure

EtCOOH + $NaN H_{2}$ $\to$ $EtCO O^{-} N a^{+}$ + gas A

EtCOOH + NaH $\to$ $EtCO O^{-} N a^{+}$ + gas B

If A and B are the molar masses of the two gases, find the value of A + B - 14.

TestHub · Accepted Answer

NaN H 2 ​ is deprotonated by the carboxylic acid, releasing ammonia : gas A = N H 3 ​ , molar mass 17. NaH is deprotonated by the acid, releasing hydrogen : gas B = H 2 ​ , molar mass 2. A + B - 14 = 17 + 2 - 14 = 5.

Chemistry - GOC Question with Solution | TestHub

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