Predict the direction of the following equilibrium and the approximate value of Keq.
NaCN + HCOOH $⇌$ HCN + HCOONa ( $p K_{a}$ : HCOOH = 3.75, HCN = 9.2)

Question

Predict the direction of the following equilibrium and the approximate value of Keq. NaCN + HCOOH ⇌ HCN + HCOONa ( p K a ​ : HCOOH = 3.75, HCN = 9.2)

TestHub · Accepted Answer

The acid on the left is HCOOH ( p K a ​ 3.75) and the acid on the right is HCN ( p K a ​ 9.2). HCN is the much weaker acid, so the equilibrium lies far to the right. Keq ≈ 1 0 9 ⋅ 2 − 3 ⋅ 75 = 1 0 5 ⋅ 45 ⋅

Chemistry - GOC Question with Solution | TestHub

Options:

Doubts & Discussion