Chemistry - GOC Question with Solution | TestHub

For the indicated carbon-bound hydrogens, the negatively charged ${\mathrm{O}}^{-}$ in 2 destabilizes another developing negative charge by electron donation, so b is the least acidic. The positive ${\mathrm{NH}}_3^{+}$ group in 3 withdraws inductively and stabilizes the carbanion, making c the most acidic. Thus c > a > b; A and $\mathrm{C}$ are consistent. Species 2 is the strongest base because it is an alkoxide; neutral 1 is more basic than ammonium-containing 3. Therefore 2 > 1 > 3, and $\mathrm{D}$ (2 > 3 > 1) is incorrect.