Arrange the ortho (I), meta (II) and para (III) methoxybenzyl carbocations in decreasing order of stability.
(I)
(II)
(III)

Question

Arrange the ortho (I), meta (II) and para (III) methoxybenzyl carbocations in decreasing order of stability. (I) (II) (III)

TestHub · Accepted Answer

OCH₃ is a strong +R donor from ortho and para, which stabilises the cation. From the meta position only its -I effect acts, and that destabilises the cation, so meta is the least stable.

At ortho the -I effect is stronger because the group is closer, which lowers the net stabilisation. Para is therefore the best.

Order : III $>$ I $>$ II.

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