Chemistry - GOC Question with Solution | TestHub

(A) $\mathrm{A}{\mathrm{g}}^{+}$ removes $\mathrm{C}{\mathrm{l}}^{-}$ and gives the aromatic cyclopropenyl cation (2π). (B) \mathrm{S_N_{1}} ionisation would give the planar cyclohexadienyl cation with 4 π electrons in the ring (anti-aromatic), which is very unstable, so the reaction does not proceed. (C) $\mathrm{A}{\mathrm{g}}^{+}$ removes $\mathrm{C}{\mathrm{l}}^{-}$ and gives the aromatic tropylium cation (6π). (D) two electrons from the metal give the aromatic cyclooctatetraene dianion (10π). So (B).