Chemistry - GOC Question with Solution | TestHub

A places amines weakened by nearby electron-withdrawing or positively charged groups above methylamine. $\mathrm{B}$ incorrectly puts ammonia above methylamine. $\mathrm{C}$ starts with pyridine > pyrrole > piperidine, although the available ${\mathrm{sp}}^3$ lone pair of piperidine makes it much more basic than pyrrole. Therefore none of A-$\mathrm{C}$ is a correct complete order.