Chemistry - GOC Question with Solution | TestHub

$\mathrm{C}{\mathrm{H}}_3\underset{\mathrm{O}\mathrm{H}}{\stackrel{\mathrm{H}}{\stackrel{|\mathrm{ }}{\underset{|\mathrm{ }}{\mathrm{C}\mathrm{*}}}}—}\underset{\mathrm{O}\mathrm{H}}{\stackrel{\mathrm{H}}{\stackrel{|\mathrm{ }}{\underset{|\mathrm{ }}{\mathrm{C}\mathrm{*}}}}—}\mathrm{C}{\mathrm{O}}_2\mathrm{H}$

It has two chiral centres so optical isomers$=2^{\mathrm{n}}=2^2=4$



Structure (I) and (II) form a pair of enantiomers. Similarly, structure (III) and (IV) also form a pair entiomers. Structure (I) or (II) does not have a plane of symmetry bisecting the bond between the two asymmetric carbon atoms. Hence, this compound exists in four isomeric forms, which are optically active.