Consider the following carbanions 1 . C H 3 - C ⊖ H 2 2 . C H 2 = C ⊖ H 3 . C H ≡ C ⊖ Correct the order of stability of these carbanions in decreasing order is

Stability of carbanion (when hybridisation of C ⊖ is different) is directly proportional to S character. Stability ∝ s%

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ChemistryGOCMiscellaneous/MixedEasy2 minPYQ_2020

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Consider the following carbanions

$1 .$ $C H_{3} - \overset{⊖}{C} H_{2}$ $2 .$ $C H_{2} = \overset{⊖}{C} H$ $3 .$ $C H \equiv \overset{⊖}{C}$

Correct the order of stability of these carbanions in decreasing order is

Options:

Answer:

Solution:

Stability of carbanion (when hybridisation of $\overset{⊖}{C}$ is different) is directly proportional to S character.
Stability $\propto$ s%

Stream:NTA_ABHYASSubject:ChemistryTopic:GOCSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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