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ChemistryGOCMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasynumerical

Total number of stereoisomers of the given compound

will be

Answer:

4.00

Solution:

Total number of stereo isomers = $2^{n - 1}$
$= 2^{3 - 1}$
$= 2^{2}$
$= 4$
Here, $n$ = number of chiral centres

Stream:NTA_ABHYASSubject:ChemistryTopic:GOCSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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