Chemistry - GOC Question with Solution | TestHub

$-\mathrm{C}\mathrm{O}\mathrm{O}\mathrm{H}>-\mathrm{C}{\mathrm{H}}_3$

$-\mathrm{C}\left(\mathrm{O}\mathrm{H}\right)\mathrm{C}\mathrm{H}(\mathrm{C}{\mathrm{H}}_3{)}_2>-\mathrm{H}$

In this compound, the heavier groups attached to the double bonded carbon atoms are at the opposite side, so the configuration of second carbon is E.

The fourth carbon can be represent as



Priority for$\mathrm{R}-\mathrm{S}$configuration,

$\mathrm{O}\mathrm{H}>=\mathrm{b}\mathrm{o}\mathrm{n}\mathrm{d}>\mathrm{R}\text{ group}>\mathrm{H}$

Since, the least prior group is attached to solid line, the clockwise$1\to 2\to 3$rotation gives S-configuration.