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ChemistryGOCMiscellaneous/MixedEasy2 minPYQ_2020
ChemistryEasysingle choice

The specific rotation of a pure enantiomer is+10°. The observed rotation, if it is isolated from a reaction with 30% racemisation and 70% inversion is

Options:

Answer:
D
Solution:

Specific rotation of inverted isomer=-10°

Angle of rotation=(Specific rotation of inverted isomer)×(Fraction of inversion)

=-10×70100=-7°

Stream:NTA_ABHYASSubject:ChemistryTopic:GOCSubtopic:Miscellaneous/Mixed
2mℹ️ Source: PYQ_2020

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