Homolytic fission of the following alkanes forms free radicals CH 3 − CH 3 , CH 3 − CH 2 − CH 3 , ( CH 3 ) 2 CH − CH 3 , CH 3 − CH 2 − CH ( CH 3 ) 2 . Increasing orders of stab

Question

Homolytic fission of the following alkanes forms free radicals $CH_{3} - CH_{3}$ , $CH_{3} - CH_{2} - CH_{3}, (CH_{3})_{2} CH - CH_{3}$ , $CH_{3} - CH_{2} - CH (CH_{3})_{2}$ . Increasing orders of stability of the radicals is:NEET 2013 (Karnataka)

Options:

Answer:

B

Solution:

One of the factor that determines the stability of radicals is hyper conjugation. $(CH_{3})_{3} \dot{C}$ show the maximum hyperconjugation.

TestHub · Accepted Answer

One of the factor that determines the stability of radicals is hyper conjugation. ( CH 3 ​ ) 3 ​ C ˙ show the maximum hyperconjugation.

Chemistry - GOC Question with Solution | TestHub

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