Arrange the carbanions, ( CH 3 ) 3 C , C Cl 3 , ( CH 3 ) 2 C H , C 6 H 5 C H 2 , in order of their decreasing stability :

2 ∘ carbanion is more stable than 3 ∘ and Cl is − 1 effect group.

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ChemistryGOCRESONANCE AND MESOMERIC EFFECTMedium2 minPYQ_2009

ChemistryMediumsingle choice

Arrange the carbanions, $(CH_{3})_{3} \overline{C}, \overline{C} Cl_{3}, (CH_{3})_{2} \overline{C} H, C_{6} H_{5} \overline{C} H_{2}$ , in order of their decreasing stability :

Options:

Answer:

Solution:

$2^{\circ}$ carbanion is more stable than $3^{\circ}$ and $Cl$ is $- 1$ effect group.

Stream:JEESubject:ChemistryTopic:GOCSubtopic:RESONANCE AND MESOMERIC EFFECT

⏱ 2mℹ️ Source: PYQ_2009

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