Chemistry - GOC Question with Solution | TestHub

Aniline is weaker base than ammonium chloride. In ${\mathrm{NH}}_4\mathrm{Cl}$ or aliphatic amines, nonbonding electron pair of $\mathrm{N}$ is localised and is fully available for coordination with a proton. $\begin{array}{rl}& {\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{NH}}_3^{\oplus }⟶{\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{NH}}_2+{\mathrm{H}}^{+}\\ & \text{(stronger acid) }\text{ (weaker-conjugate base) }\\ & \end{array}$ (stronger acid) (weaker-conjugate base) On the other hand, in aniline and other aromatic amines, the non-bonding electron pair is delocalised into benzene ring by resonance.