Chemistry - GENERAL CHEMISTRY Question with Solution | TestHub

Electronic configuration of an ion $\left[{\mathrm{M}}^{+]}\right]$is $[\mathrm{Ar}]3{\mathrm{d}}^{10}$, so electronic configuration of M is $[\mathrm{Ar}]3{\mathrm{d}}^{10},4{\mathrm{s}}^1$. Atomic number of $M$ is 29 so atomic number of elements which is just below $M$ in the periodic table is 47.